[root@hn ~]# fdisk /dev/sdb
The device presents a logical sector size that is smaller than
the physical sector size. Aligning to a physical sector (or optimalI/O) size boundary is recommended, or performance may be impacted.欢迎使用 fdisk (util-linux 2.23.2)。更改将停留在内存中,直到您决定将更改写入磁盘。
使用写入命令前请三思。 命令(输入 m 获取帮助):nPartition type: p primary (1 primary, 0 extended, 3 free) e extendedSelect (default p): p分区号 (2-4,默认 2):起始 扇区 (476773168-976773167,默认为 476774400):将使用默认值 476774400Last 扇区, +扇区 or +size{K,M,G} (476774400-976773167,默认为 976773167):将使用默认值 976773167分区 2 已设置为 Linux 类型,大小设为 238.4 GiB命令(输入 m 获取帮助):w
The partition table has been altered!Calling ioctl() to re-read partition table.
WARNING: Re-reading the partition table failed with error 16: 设备或资源忙.
The kernel still uses the old table. The new table will be used atthe next reboot or after you run partprobe(8) or kpartx(8)正在同步磁盘。[root@hn ~]# ll /dev/sdsda sda1 sda2 sda3 sdb sdb1 [root@hn ~]# ll /dev/sdbsdb sdb1 [root@hn ~]# ll /dev/sdbsdb sdb1 [root@hn ~]# partprobe
[root@hn ~]# mkfs.xfs /dev/sdb1
mkfs.xfs: /dev/sdb1 appears to contain an existing filesystem (LVM2_member).mkfs.xfs: Use the -f option to force overwrite.
[root@hn ~]# mkfs.xfs -f /dev/sdb1
meta-data=/dev/sdb1 isize=256 agcount=4, agsize=14899098 blks = sectsz=4096 attr=2, projid32bit=1 = crc=0 finobt=0data = bsize=4096 blocks=59596390, imaxpct=25 = sunit=0 swidth=0 blksnaming =version 2 bsize=4096 ascii-ci=0 ftype=0log =internal log bsize=4096 blocks=29099, version=2 = sectsz=4096 sunit=1 blks, lazy-count=1realtime =none extsz=4096 blocks=0, rtextents=0